Web20 mei 2012 · May 20, 2012 at 12:51. Show 7 more comments. 2. For the generalisation to k digits, the most obvious way is to do something like: palindromes = [x for x in itertools.permutations (string.digits, k) if x == x [::-1]] But it isn't very efficient - it generates every possible 3-digit number, and discards the ones that aren't palindromes. WebWij willen hier een beschrijving geven, maar de site die u nu bekijkt staat dit niet toe.
Palindromic prime - Wikipedia
WebAnswer (1 of 9): [i for i in range(100000,1000000) if getDigit(0,i) == getDigit(5,i) and getDigit(1,i) == getDigit(4,i) and getDigit(2,i) == getDigit(3,i) and i % 11 ... Web'BOB' is a palindrome. Because date formats vary from country to country, not all dates that are palindromic in one kind of date format are Palindrome Days in another. For instance, March 21, 2024 or 3-21-23 was a palindromic date in the m-dd-yy format, but it wasn't if you write the date as dd-m-yyyy (21-3-2024) or dd-mm-yyyy formats (21-03-2024). is it safe to get botox while pregnant
What are all five digit palindromes? - Answers
WebThe first few (base-10) palindromic primes are 2, 3, 5, 7, 11, 101, 131, 151, 181, 191, 313, 353, 373, 383, 727, 757, 787, ... (OEIS A002385 ; Beiler 1964, p. 228). The number of palindromic primes less than a given … Web22 mei 2016 · There are 9 ⋅ 10 n 2 − 1 such numbers. And each of those numbers can be used to create a palindromic number merely by writing the next n / 2 digits as that number written backward! All palindromes of even length are formed that way. So the answer is there are. 9 ⋅ 10 n 2 − 1. keto side dish recipes for dinner