WebOct 12, 2024 · Given, F irst term, T1 = k^2 + 4k + 8. Given, Second term, T2 = 2k^2 + 3k + 6. Given,Third term, T3 = 3k^2 + 4k + 4. Given, They are 3 consecutive terms of an AP. … WebDec 17, 2024 · Answer: K=0 Step-by-step explanation: Since, k2 + 4k + 8,2k2 + 3k + 6 and 3k2 + 4k + 4 are consecutive terms of an AP ∴ 2k2 + 3k + 6 – (k2 + 4k + 8) = 3k2 + 4k + 4 – (2k2 + 3k + 6) = Common difference ⇒ 2k2 + 3k + 6 - k2 - 4k - 8 = 3k2 + 4k + 4 - 2k2 - 3k - 6 ⇒ k2 - k - 2 = k2 + k - 2 ⇒ -k = k ⇒ 2k = 0 ⇒ k = 0 Advertisement New questions in Math
Determine the value of k for which k^2 + 4k + 8, 2k^2 + 3k + 6 …
Web2. As you probably have already realized the formula n ∑ k = 1k3 = (n(n + 1) 2)2 can be proved using induction. For n = 1 you have 13 = (1 ⋅ 2 2)2. Say that the formula holds for n and prove that it holds for n = 1. So you have/get n + 1 ∑ k = 1k3 = [ n ∑ k = 1k3] + (n + 1)3 = n2(n + 1)2 22 + (n + 1)3. WebDetermine k so that k+ 4k + 8, 2k + 3k + 6, 3k + 4k + 4 are . Solution: An arithmetic progression (AP) is a sequence where the differences between every two consecutive terms are the same. k + 4k + 8, 2k + 3k + 6 and 3k + 4k+ 4 are consecutive terms of an AP. Therefore, k is 0. nousouken-zoom tdfaff.com
Determine k , so that k^2 + 4k + 8 , 2k^2 + 3k + 6 and 3k^2 + 4k …
WebFind the value of k if k2 4k 8 2k2 3k 8 and 3k2 4k 4 are 3 consecutive terms of an ap - Determine k, so that `K^(2)+4k+8, 2k^(2)+3k+6` and `3k^(2)+4k+4` are. Math Tutor. Solve Now! ... Find the value of k, if k2 + 4k + 8, 2k2 + 3k + 4 and 3k2 + 4k + 4 An arithmetic progression (AP) is a sequence where the differences between every two ... WebDetermine k, so that k2+4k+8,2k2+3k+6 and 3k2+4k+4 are three consecutive terms of an AP. Solution Given, k2+4k+8,2k2+3k+6 and 3k2+4k+4 are consecutive terms of an AP. … WebAug 26, 2024 · Determine k, so that k2 + 4k + 8, 2k2 + 3k + 6 and 3k2 + 4k + 4 are three consecutive terms of an AP. arithmetic progression class-10 Share It On Facebook … how to sign up for snap benefits online in ky